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Ackermann function in Dhall
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| -- Credit to: https://news.ycombinator.com/item?id=15186988 | |
| let iterate | |
| : (Natural → Natural) → Natural → Natural | |
| = λ(f : Natural → Natural) | |
| → λ(n : Natural) | |
| → Natural/fold (n + 1) Natural f 1 | |
| let increment : Natural → Natural = λ(n : Natural) → n + 1 | |
| let ackermann | |
| : Natural → Natural → Natural | |
| = λ(m : Natural) → Natural/fold m (Natural → Natural) iterate increment | |
| in ackermann |
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