Erlang exercise nub

nub.erl

-module(nub).

-export([test/0,nub/1]).


-spec nub(list()) -> list().
nub(L) -> nub(L,[]).

%Adds non repeated elements to the list.
-spec nub(list(),list()) -> list().
nub([],Acc) -> 
	lists:reverse(Acc);
nub([H|T],Acc) -> 
	case inlist(H,Acc) of
		true -> nub(T,Acc);
		false -> nub(T,[H|Acc])
	end.

%returns true if the element is already in list.
-spec inlist(integer(),list()) -> boolean().
inlist(_,[]) -> false;
inlist(X,[X|_]) -> true;
inlist(X,[_|T]) -> inlist(X,T).


test() ->
	[1,2,3,43,435] = nub:nub([1,2,3,43,435,2,2,2,2]),
	ok.

Oh okay, I didn't understand the difference betwen list() and [T], now i do.
Thanks again.