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Recursive Contains
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// solution to problem #6 in recursive exercises | |
function contains(object, searchValue) { | |
// because `null` has a typof "object", we have to explicitly check | |
// to prevent trying to access `null`'s values (which don't exist) | |
if (typeof object !== "object" || object === null) { | |
return object === searchValue; | |
} | |
for (const value of Object.values(object)) { | |
// An important problem in the code quiz solution is that `return contains()` will only | |
// search the first property of an object, as it will return whatever the result for it is. | |
// If our value was nested within the second property, for example, it would never get checked | |
// even if the first nested object did not contain it. | |
if (contains(value, searchValue)) { | |
return true; | |
} | |
} | |
return false; | |
} |
Came up with this function myself:
function contains(obj, targetVal) {
for (const currentVal of Object.values(obj)) {
if (typeof currentVal === "object") {
return contains(currentVal, targetVal);
}
if (currentVal === targetVal) return true;
}
return false;
}
Felt quite good about it even though I knew that a null
could very easily render it useless. But then I realised that I could just change the third line to: if (typeof currentVal === "object" && currentVal !== null) {
to prevent that from happening.
I thought I needed to search for the keys and values:
function contains(obj, item) {
if (Object.values(obj).length === 0) return false;
else if (item in obj || Object.values(obj).includes(item)) return true;
else {
for (let value of Object.values(obj)) {
return contains(value, item);
}
}
}
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Just adding another recursive solution here that utilizes Array.prototype.some, nice and succinct:
I had originally used a ternary statement (below) as the callback for .some(), which felt a bit easier to read to me, but for the sake of keeping it short, modified to the above.