Different solutions for Fizz Buzz in Ruby

fizzbuzz.rb

def fizz_buzz_1(max)
  arr = []
  (1..max).each do |n|
    if ((n % 3 == 0) && (n % 5 == 0))
      arr << "FizzBuzz"
    elsif (n % 3 == 0)
      arr << "Fizz"
    elsif (n % 5 == 0)
      arr << "Buzz"
    else
      arr << n
    end
  end
  return arr
end

def fizz_buzz_2(max)
  arr = []
  (1..max).each do |n|
    if (n % 3 == 0)
      if (n % 5 == 0)
        arr << "FizzBuzz"
      else
        arr << "Fizz"
      end
    elsif (n % 5 == 0)
      arr << "Buzz"
    else
      arr << n
    end
  end
  return arr
end

def fizz_buzz_3(max)
  arr = []
  (1..max).each do |n|
    text = ""
    if (n % 3 == 0)
      text << "Fizz"
    end
    if (n % 5 == 0)
      text << "Buzz"
    end
    if !((n % 3 == 0) || (n % 5 == 0))
      text = n
    end
    arr << text
  end
  return arr
end

require "fizzbuzz"

RSpec.describe FizzBuzz do
  describe "#compute" do
    context "when number is dvisisble by 3" do
      it "returns fizz" do
        expect(FizzBuzz.compute(6)).to eq("fizz")
      end
    end

    context "when number is dvisisble by 5" do
      it "returns buzz" do
        expect(FizzBuzz.compute(10)).to eq("buzz")
      end
    end

    context "when number is dvisisble by both 3 and 5" do
      it "returns buzz" do
        expect(FizzBuzz.compute(15)).to eq("fizzbuzz")
      end
    end
  end
end


class FizzBuzz
  def self.compute(number)
    return "fizzbuzz" if (number % 15).zero?

    if (number % 3).zero? "fizz" else "buzz" end
  end
end

for n in 1..101
  print "Fizz" if n%3 == 0
  print "Buzz" if n%5 == 0
  print n unless n%3 == 0 || n%5 == 0
  print "\n"
end

(1..100).each_with_object([]) do |number, array|
  next array << "FizzBuzz" if number % 15 == 0
  next array << "Fizz" if number % 3 == 0
  next array << "Buzz" if number % 5 == 0

  array << number
end