Created
April 4, 2024 14:35
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class Solution { | |
public int solution(int[] A) { | |
int[] dp = new int[31]; // dp[i] stores the minimum cost to travel up to day i | |
int n = A.length; | |
int travelIndex = 0; // pointer to the current travel date | |
for (int i = 1; i <= 30; i++) { | |
if (travelIndex < n && i == A[travelIndex]) { // if i is a travel date | |
int oneDayCost = dp[i - 1] + 2; // cost if using a 1-day ticket on day i | |
int sevenDayCost = i > 7 ? dp[i - 7] + 7 : 7; // cost if using a 7-day ticket on day i | |
int thirtyDayCost = dp[i - 30] + 25; // cost if using a 30-day ticket on day i | |
dp[i] = Math.min(oneDayCost, Math.min(sevenDayCost, thirtyDayCost)); | |
travelIndex++; // move to the next travel date | |
} else { | |
dp[i] = dp[i - 1]; // no travel on day i, cost same as previous day | |
} | |
} | |
return dp[30]; // return the minimum cost for the whole month | |
} | |
} |
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