Detect OS and Architecture cross platform testing

detectOS.cmd

#!/usr/bin/env bash
@echo off

goto(){

function checkOS() {
	unameOut="$(uname -s)"
	case "${unameOut}" in
		*Microsoft*)     OS="WSL";; #must be first since Windows subsystem for linux will have Linux in the name too
    	*microsoft*)     OS="WSL2";;
    	Linux*)     OS="Linux";;
    	Darwin*)    OS="MacOS";; 
    	CYGWIN*)    OS="Cygwin";;
    	MINGW*)     OS="Windows";;
    	*Msys)     OS="Windows";;
    	*)          OS="UNKNOWN:${unameOut}"
	esac
	echo ${OS}
}

function checkProcessor() {
	arch="$(uname -m)"
	if [[ "$arch" = x86_64* ]]; then
		if [[ "$(uname -a)" = *ARM64* ]]; then
			echo 'ARM64'
		else
			echo 'x86_64'
		fi # was going to use /usr/sbin/sysctl -n machdep.cpu.brand_string but this nested if works detecting ARM for now. I think
	elif [[ "$arch" = i*86 ]]; then
		echo 'i*86'
	elif [[ "$arch" = arm* ]]; then
		echo 'ARM64'
	elif test "$arch" = aarch64; then
		echo 'aarch64'
	else
		echo "UNKNOWN:${arch}"
	fi
}

}

checkOS
checkProcessor
goto $@
read -rsp $'Press enter to continue...\n'
exit

:(){
rem Windows script here
FOR /F "tokens=*" %%o IN ('echo %OS%') do (SET unameOut=%%o)
FOR /F "tokens=*" %%p IN ('echo %PROCESSOR_ARCHITECTURE%') do (SET arch=%%p)

echo "Operating System is %unameOut%"
echo "Processor Architecture is %arch%"
rem pause
exit