Scrape smittestop status

smittestop-scrape.py

import re
import time
import httpx

URL = "https://smittestop.dk/status/"

r = httpx.get(URL)

assert r.status_code == 200, f'{r.status_code}: {r.content}'

# Antal downloads af smitte|stop: <strong data-v-e17f8414>1.832.245</strong>
# Antal smittemeldinger i appen: <strong data-v-e17f8414>14.365</strong>
pattern = re.compile(r'\>(?P<name>[^>]+): \<strong data-v-[a-z0-9]+\>(?P<num>[0-9\.]+)\</strong\>')

print(f'\nTime:\t{int(time.time())}')
for k, v in pattern.findall(r.content.decode()):
    print(f'{k}:\t{v}')

# I'm scraping this every hour. Contact me to get the data :)