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public class FriendCircles { | |
private int count; | |
public int findCircleNum(int[][] M) { | |
count = M.length; | |
int len = M.length; | |
int[] circles = new int[len]; | |
int[] rank = new int[len]; | |
for (int i = 0; i < len; i++) { | |
circles[i] = i; | |
} | |
for (int i = 0; i < len; i++) { | |
for (int j = 0; j < len; j++) { | |
if (M[i][j] == 1) { | |
union(circles, rank, i, j); | |
} | |
} | |
} | |
return count; | |
} | |
public void union(int[] circles, int[] rank, int i, int j) { | |
int root1 = findCircle(circles, i); | |
int root2 = findCircle(circles, j); | |
if (root1 == root2) return; | |
if (rank[root1] < rank[root2]) { | |
circles[root1] = root2; | |
} else if (rank[root1] > rank[root2]) { | |
circles[root2] = root1; | |
} else { | |
circles[root1] = root2; | |
rank[root1] += 1; | |
} | |
count--; | |
} | |
public int findCircle(int[] circles, int i) { | |
while (circles[i] != i) { | |
// path compression by halving | |
circles[i] = circles[circles[i]]; | |
i = circles[i]; | |
} | |
return i; | |
} | |
} |
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