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Calculates the partition function with Python
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# Copyright (c) 2017 Christian Calderon | |
# | |
# Permission is hereby granted, free of charge, to any person obtaining a copy | |
# of this software and associated documentation files (the "Software"), to deal | |
# in the Software without restriction, including without limitation the rights | |
# to use, copy, modify, merge, publish, distribute, sublicense, and/or sell | |
# copies of the Software, and to permit persons to whom the Software is | |
# furnished to do so, subject to the following conditions: | |
# | |
# The above copyright notice and this permission notice shall be included in all | |
# copies or substantial portions of the Software. | |
# | |
# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR | |
# IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, | |
# FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE | |
# AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER | |
# LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, | |
# OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE | |
# SOFTWARE. | |
from __future__ import print_function, division | |
import math | |
import sys | |
if 3 == sys.version_info.major: | |
xrange = range | |
def range(*args): | |
return list(xrange(*args)) | |
KNOWNS = [ | |
1, 1, 2, 3, 5, 7, 11, 15, 22, | |
30, 42, 56, 77, 101, 135, 176, | |
231, 297, 385, 490, 627, 792, 1002, | |
1255, 1575, 1958, 2436, 3010, 3718, | |
4565, 5604, 6842, 8349, 10143, 12310, | |
14883, 17977, 21637, 26015, 31185, 37338, | |
44583, 53174, 63261, 75175 | |
] | |
PENTS = [ | |
1, 2, 5, 7, 12, 15, 22, | |
26, 35, 40, 51, 57, 70, | |
77, 92, 100, 117, 126, | |
145, 155, 176, 187, 210, | |
222, 247, 260, 287, 301, | |
330, 345, 376, 392, 425, | |
442, 477, 495, 532, 551, | |
590, 610, 651, 672, 715, | |
737, 782, 805, 852, 876, | |
925, 950, 1001, 1027, | |
1080, 1107, 1162, 1190, | |
1247, 1276 | |
] | |
TIME_UNITS = ( | |
('years', 31556952), | |
('weeks', 604800), | |
('days', 86400), | |
('hours', 3600), | |
('minutes', 60) | |
) | |
def print_time(t): | |
result = 'Time: ' | |
for name, amount in TIME_UNITS: | |
r, t = divmod(t, amount) | |
if r: | |
result += '%s %d, ' % (name, r) | |
result += '%3.1f seconds.' % t | |
print(result) | |
def partitions1(n, VALS={0:1}): | |
"""Partition count via restricted partition identity, w/ simulated recursion.""" | |
if n == 0: | |
return 1 | |
# uses Cantor's pairing function to assign an index to each pair: | |
# idx(n, k) = (n + k)*(n + k + 1)/2 + k | |
# the largest index goes to the pair n, n | |
# idx(n, n) = (n + n)*(n + n + 1)/2 + n | |
# = 2n*(2n + 1)/2 + n | |
# = 2n**2 + 2n | |
ns = range(n) | |
stack = [(n, n - i) for i in ns] | |
push = stack.append | |
pop = stack.pop | |
while stack: | |
n, k = stack[-1] | |
idx = (n + k)*(n + k + 1)//2 + k | |
if idx in VALS: | |
pop() | |
continue | |
if n == 0 or k == 0 or n < k: | |
VALS[idx] = 0 | |
pop() | |
continue | |
if k == 1 or k == n or k + 1 == n: | |
VALS[idx] = 1 | |
pop() | |
continue | |
if k == 2: | |
VALS[idx] = n//2 | |
pop() | |
continue | |
t1_idx = n*(n + 1)//2 + k | |
t2_idx = (n + k - 2)*(n + k - 1)//2 + k - 1 | |
t1_check = t1_idx in VALS | |
t2_check = t2_idx in VALS | |
if t1_check and t2_check: | |
VALS[idx] = VALS[t1_idx] + VALS[t2_idx] | |
pop() | |
continue | |
if not t1_check: | |
push((n - k, k)) | |
if not t2_check: | |
push((n - 1, k - 1)) | |
return sum(VALS[2*n*(n - i +1) + (i*(i - 3) >> 1)] for i in ns) | |
def partitions2(n, VALS=KNOWNS[:]): | |
"""Partition count via pentagonal number theorem, w/ simulated recursion.""" | |
if n < len(VALS): | |
return VALS[n] | |
else: | |
VALS += (n - len(VALS) + 1)*[0] | |
pents = [] | |
append = pents.append | |
i = 1 | |
p = 1 | |
while p <= n: | |
append(p) | |
i += 1 | |
j = ((i - 1) >> 1) + 1 | |
if not i&1: | |
j = -j | |
p = (3*j*j - j) >> 1 | |
append(p) | |
stack = [n] | |
push = stack.append | |
pop = stack.pop | |
while stack: | |
m = stack[-1] | |
if VALS[m]: | |
pop() | |
continue | |
i = 0 | |
sign = 1 | |
k = m - 1 | |
result = 0 | |
keep_adding = True | |
while k >= 0: | |
if keep_adding and VALS[k]: | |
result += sign*VALS[k] | |
elif not VALS[k]: | |
push(k) | |
keep_adding = False | |
i += 1 | |
if not i&1: | |
sign = -sign | |
k = m - pents[i] | |
if keep_adding: | |
VALS[m] = result | |
pop() | |
return VALS[n] | |
def partitions3(n, vals=KNOWNS[:], pents=PENTS): | |
"""Partition count via pentagonal number theorem.""" | |
l = len(vals) | |
if n < l: | |
return vals[n] | |
else: | |
vals.extend((n - l + 1)*[0]) | |
# 0 -> 1 | |
# 1 -> -1 | |
# 2 -> 2 | |
# 3 -> -2 | |
# 4 -> 3 | |
# 5 -> -3 | |
# 6 -> 4 | |
# 7 -> -4 | |
# j -> (-1)^j * (floor(j/2) + 1) | |
# -> (-1)**(j&1) * (j//2 + 1) = k | |
# | |
# pentagonal numbers | |
# k(3k - 1)/2 = P_k | |
# k(3k - 1) - 2P_k = 0 | |
# 3k^2 - k - 2P_k = 0 | |
# k = (1 +- sqrt(1 + 24P_k))/6 | |
# | |
# If k > 0 then floor(j/2) + 1 == k => j = 2(k - 1) | |
# If k < 0 then j = 2(-k - 1) + 1 | |
# | |
# k1 = floor((1 + sqrt(1 + 24n))/6), j1 = 2(k1 - 1) | |
# k2 = ceil((1 - sqrt(1 + 24n))/6), j2 = 2(-k2 - 1) + 1 | |
# j1 > j2 => compute up to (including) j1 + 1 | |
# j2 > j1 => compute up to (including) j2 + 1 | |
if n > pents[-1]: | |
k1 = int((1 + (1 + 24*n)**0.5)/6) | |
j1 = 2*(k1 - 1) | |
k2 = int((1 - (1 + 24*n)**0.5)/6) | |
j2 = 2*(-k2 - 1) + 1 | |
max_j = max(j1, j2) + 2 | |
start_j = len(pents) | |
pents.extend([k*(3*k - 1)//2 for k in [(-1)**(j&1)*(j//2 + 1) for j in range(start_j, max_j)]]) | |
q_is = range(len(pents)) | |
for m in range(l, n+1): | |
result = 0 | |
sign = -1 | |
for i in q_is: | |
if not i&1: | |
sign = -sign | |
p_i = pents[i] | |
if m < p_i: | |
break | |
result += sign*vals[m - p_i] | |
vals[m] = result | |
return vals[n] | |
def test(): | |
for i, val in enumerate(KNOWNS): | |
result = partitions1(i) | |
assert val == result | |
print('TEST PASSED') | |
def timeit(n, f): | |
print('Running', f.__name__, '...') | |
start = time.time() | |
result = f(n) | |
end = time.time() | |
print_time(end - start) | |
print('Result:', result) | |
return result | |
def compare(n): | |
r1 = timeit(n, partitions1) | |
r2 = timeit(n, partitions2) | |
r3 = timeit(n, partitions3) | |
if r1 == r2 == r3: | |
print('PASSED') | |
else: | |
print('FAILED') | |
if __name__ == '__main__': | |
import cProfile | |
import time | |
if sys.argv[1] == 'calc3': | |
timeit(int(sys.argv[2]), partitions3) | |
elif sys.argv[1] == 'calc2': | |
timeit(int(sys.argv[2]), partitions2) | |
elif sys.argv[1] == 'calc1': | |
timeit(int(sys.argv[2]), partitions1) | |
elif sys.argv[1] == 'test': | |
test() | |
elif sys.argv[1] == 'profile': | |
cProfile.run('partitions{}({})'.format(sys.argv[2], sys.argv[3])) | |
elif sys.argv[1] == 'compare': | |
compare(int(sys.argv[2])) |
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