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August 27, 2024 03:22
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JavaScript Mastery - Kata 5
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// In this exercise, you will be given a normal string | |
// of words and will turn it into a percent-encoded string | |
// by replacing all whitespace with %20. | |
// Percent Encoding | |
// Take a look at the following URL, specifically the last | |
// part: | |
// This URL will perform a Google search for the term "lighthouse labs". | |
// Notice that when the string "lighthouse labs" is part of a URL, the | |
// space is replaced with %20. | |
// If you want to add a parameter to a URL, there are certain characters | |
// that must be encoded in order to make the URL valid. There are many | |
// characters that must be encoded, including: , !, ", and #. | |
// For this exercise, you will only be focusing on replacing the space | |
// with %20. | |
// Input | |
// const urlEncode = function(text) { | |
// // Put your solution here | |
// }; | |
// console.log(urlEncode("Lighthouse Labs")); | |
// console.log(urlEncode(" Lighthouse Labs ")); | |
// console.log(urlEncode("blue is greener than purple for sure")); | |
// Expected Output | |
// Lighthouse%20Labs | |
// Lighthouse%20Labs | |
// blue%20is%20greener%20than%20purple%20for%20sure | |
// Instruction | |
// Create a function named urlEncode that will receive a string of words, | |
// and return that string with all of the whitespace characters converted | |
// to %20. If there is whitespace on the outside of the string, | |
// like in the second example | |
// above, you should only replace the whitespace within the string. | |
let url = " this is a sample" | |
function urlEncodeSpace(url){ | |
let encodedString = '' | |
for ( i in url){ | |
// console.log(url[i]) | |
if(url[i] === ' '){ | |
encodedString += "%20" | |
}else { | |
encodedString += url[i] | |
} | |
if(encodedString[0] === " "){ | |
encodedString.pop() | |
} | |
} | |
return encodedString; | |
} | |
console.log(urlEncodeSpace(url)) |
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