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import numpy as np | |
import matplotlib.pyplot as pl | |
import scipy.stats as st | |
import theano.tensor as tt | |
import theano.tensor.slinalg as sl | |
from ipdb import set_trace as stop | |
from sklearn.neighbors import NearestNeighbors | |
def chol_invert(A): | |
""" | |
Return the inverse of a symmetric matrix using the Cholesky decomposition. The log-determinant is | |
also returned | |
Args: | |
A : (N,N) matrix | |
Returns: | |
AInv: matrix inverse | |
logDeterminant: logarithm of the determinant of the matrix | |
""" | |
L = np.linalg.cholesky(A) | |
LInv = np.linalg.inv(L) | |
AInv = np.dot(LInv.T, LInv) | |
logDeterminant = -2.0 * np.sum(np.log(np.diag(LInv))) # Why the minus sign? | |
return AInv, logDeterminant | |
def covariance(x, lambda_gp, sigma_gp): | |
return sigma_gp * np.exp(-0.5 * lambda_gp * x**2) | |
N = 10 | |
x = np.linspace(0,8,N) | |
mean = np.zeros((N)) | |
K = covariance(x[None,:] - x[:,None], 1.0, 1.0) | |
x_test = np.ones((N)) | |
print(st.multivariate_normal.logpdf(x_test, mean=mean, cov=K)) | |
nbrs = NearestNeighbors(n_neighbors=8, algorithm='ball_tree').fit(np.atleast_2d(x).T) | |
distances, indices = nbrs.kneighbors(np.atleast_2d(x).T) | |
K_inv, logdet_K = chol_invert(K) | |
print(-0.5 * N * np.log(2.0*np.pi) - 0.5 * logdet_K - 0.5 * (x_test-mean).T @ K_inv @ (x_test-mean)) | |
A = tt.as_tensor(np.zeros_like(K)) | |
D_inv = tt.as_tensor(np.zeros_like(K)) | |
I = tt.as_tensor(np.identity(N)) | |
D_inv = tt.set_subtensor(D_inv[0,0], K[0,0]) | |
for i in range(N-1): | |
Pa = indices[i+1,:] | |
Pa = Pa[Pa < i+1] | |
Pa2 = np.atleast_2d(Pa).T | |
A = tt.set_subtensor(A[i+1,Pa], sl.solve(K[Pa,Pa2], K[i+1,Pa])) | |
D_inv = tt.set_subtensor(D_inv[i+1,i+1], 1.0/(K[i+1,i+1] - tt.dot(K[i+1,Pa], A[i+1,Pa]))) | |
K_NNGP_inv = tt.dot(tt.dot(I - A.T, D_inv), I - A) | |
logdet_NNGP = np.sum(np.log(1.0/np.diag(D))) |
Not really. If I remember correctly, the loop was killing the efficiency and I abandoned it. Perhaps it would make sense to return to this again.
I am playing around with your code (hope you don't mind). Is this self sufficient? It seems like the for loop needs to loop through the lower triangular sparse covariance matrix A. Is this what Pa is? Also isn't D the diagnol matrix of size nxn with the std as its entries?
Update: Pa refers to the nearest neighbor indices. my bad.
Also, I think you want to calculate the diagnol D not D_inv in the for loop.
From the paper:
We can compute the nonzero elements of A and the diagonal elements of D much more efficiently as:
for(i in 1:(n-1)
{ Pa = N[i+1] # neighbors of i+1
a[i+1,Pa] = solve(K[Pa,Pa], K[(i+1),Pa])
d[i+1,i+1] = K[i+1,i+1] - dot(K[(i+1),Pa], a[i+1,Pa])
}.
Are you still working on this??!! It would be awesome to be able to use this in pymc3. NNGPs look would be really useful. How do you get the speed ups if you're having to take the cholesky and inverse of the covariance matrix? Is this only a sparse version of the covariance matrix?