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April 5, 2018 14:25
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Generate barcode .png from a .csv data source file
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import csv | |
import os | |
import requests | |
import shutil | |
import urllib | |
""" | |
Docs: http://labelary.com/service.html | |
""" | |
url = 'http://api.labelary.com/v1/printers/8dpmm/labels/3x1.5/0/' | |
data_source_file = 'data.csv' | |
output_directory = 'output' | |
if not os.path.exists(output_directory): | |
os.makedirs(output_directory) | |
with open(data_source_file, 'rb') as csvfile: | |
rows = csv.reader(csvfile, delimiter=',') | |
for identifier, barcode in rows: | |
print 'identifier: {} -- barcode: {}'.format(identifier, barcode) | |
zpl = ''.join(['^XA^BY4,5,200^FO010,10^BC^FD', barcode, '^FS^XZ']) | |
files = {'file': zpl} | |
response = requests.post(url, files=files, stream=True) | |
if response.status_code == 200: | |
response.raw.decode_content = True | |
filename = ''.join([identifier, '.png']) | |
with open(os.path.join(output_directory, filename), 'wb') as out_file: | |
shutil.copyfileobj(response.raw, out_file) | |
else: | |
print('Error: ' + response.text) |
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