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@ahafidi
Created March 26, 2025 13:25
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$$\binom{n}{k} = \frac{n!}{k! (n-k)!}$$

$$\binom{50}{5} = 2 \space 118 \space 760 \space \space \space \& \space \space \space \binom{12}{6} = 66$$

$$\binom{50}{5} \times \binom{12}{6} = 139 \space 838 \space 160$$

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