JAVASCRIPT:Remove Accents

gistfile1.txt

	 function RemoveAccents(strAccents) {
		var strAccents = strAccents.split('');
		var strAccentsOut = new Array();
		var strAccentsLen = strAccents.length;
		var accents = 'ÀÁÂÃÄÅàáâãäåÒÓÔÕÕÖØòóôõöøÈÉÊËèéêëðÇçÐÌÍÎÏìíîïÙÚÛÜùúûüÑñŠšŸÿýŽž';
		var accentsOut = "AAAAAAaaaaaaOOOOOOOooooooEEEEeeeeeCcDIIIIiiiiUUUUuuuuNnSsYyyZz";
		for (var y = 0; y < strAccentsLen; y++) {
			if (accents.indexOf(strAccents[y]) != -1) {
				strAccentsOut[y] = accentsOut.substr(accents.indexOf(strAccents[y]), 1);
			} else
				strAccentsOut[y] = strAccents[y];
		}
		strAccentsOut = strAccentsOut.join('');
		return strAccentsOut;
	}

Though I prefer the map method, here's the original but TypeScript-friendly:

private replaceAccents(str: string): string
{
    const ACCENTS = 'ÀÁÂÃÄÅàáâãäåÒÓÔÕÕÖØòóôõöøÈÉÊËèéêëðÇçÐÌÍÎÏìíîïÙÚÛÜùúûüÑñŠšŸÿýŽž';
    const NON_ACCENTS = "AAAAAAaaaaaaOOOOOOOooooooEEEEeeeeeCcDIIIIiiiiUUUUuuuuNnSsYyyZz";

    const strAccents: string[] = str.split('');
    const strAccentsOut: string[] = new Array();

    const strAccentsLen: number = strAccents.length;

    for (let y = 0; y < strAccentsLen; y++) 
    {
        if (ACCENTS.indexOf(strAccents[y]) != -1)
        {
            strAccentsOut[y] = NON_ACCENTS.substr(ACCENTS.indexOf(strAccents[y]), 1);
        } 
        else
        {
                strAccentsOut[y] = strAccents[y];
        }
    }

    const newString: string = strAccentsOut.join('');
    return newString;
}

A slight alternative to above using the string normalisation AND correct substitution for the German ß

import { includes, some } from 'lodash'

export default function convertForeignCharacters(str: string): string {
  const strAccents: string[] = str.split('')
  const strAccentsOut: string[] = new Array()

  const strAccentsLen: number = strAccents.length

  for (let y: number = 0; y < strAccentsLen; y++) {
    if (!some(['ä', 'ü', 'ö'], (el: string) => includes(strAccents[y], el))) {
      strAccentsOut[y] = strAccents[y].normalize('NFD').replace(/[\u0300-\u036f]/g, '')
    } else {
      strAccentsOut[y] = strAccents[y]
    }
  }

  const newString: string = strAccentsOut.join('').replace('ß', 'ss')
  return newString
}

O(n) version, ~5x faster, especially if you want add more accents.

const accents = 'ÀÁÂÃÄÅĄĀāàáâãäåąßÒÓÔÕÕÖØŐòóôőõöøĎďDŽdžÈÉÊËĘèéêëęðÇçČčĆćÐÌÍÎÏĪìíîïīÙÚÛÜŰùűúûüĽĹŁľĺłÑŇŃňñńŔŕŠŚŞšśşŤťŸÝÿýŽŻŹžżźđĢĞģğ',
	accents_out = "AAAAAAAAaaaaaaaasOOOOOOOOoooooooDdDZdzEEEEEeeeeeeCcCcCcDIIIIIiiiiiUUUUUuuuuuLLLlllNNNnnnRrSSSsssTtYYyyZZZzzzdGGgg",
	accents_map = new Map();
for (const i in accents)
	accents_map.set(accents.charCodeAt(i), accents_out.charCodeAt(i))

function removeAccents(str) {
	const nstr = new Array(str.length);
	let x, i;
	for (i = 0; i < nstr.length; i++)
		nstr[i] = accents_map.get(x = str.charCodeAt(i)) || x;
	return String.fromCharCode.apply(null, nstr);
}

@ArthurMaroulier
FYI: It doesn't cover all letters ('Ø' for example).

"ÀÁÂÃÄÅàáâãäåÒÓÔÕÕÖØòóôõöøÈÉÊËèéêëðÇçÐÌÍÎÏìíîïÙÚÛÜùúûüÑñŠšŸÿýŽž".normalize('NFD').replace(/[\u0300-\u036f]/g, "");
"AAAAAAaaaaaaOOOOOOØoooooøEEEEeeeeðCcÐIIIIiiiiUUUUuuuuNnSsYyyZz"

did you find a way to convert Ø please ?

https://gist.github.com/marcelo-ribeiro/abd651b889e4a20e0bab558a05d38d77

If your goal is to sort a list of strings, disregarding accents

['André', 'Álister', 'alan'].sort(new Intl.Collator('pt-BR').compare)

Or just to be safe

['André', 'Álister', 'alan'].sort(new Intl.Collator('pt-BR', {sensitivity:'base'}).compare)

Other variant could be..
const removeAccents = (str) => { return str .toLowerCase() .normalize("NFD") .replace(/[\u0300-\u036f]/g, ""); };

Hello! All the above examples are good! However, I put the function at onChange event on an input field and the next character duplicates all the string from the input. Is there any solution to prevent this? Thank you!