FizzBuzz Using C

FizzBuzz.c

#include <stdio.h>
#include <stdbool.h>

#define STARTING_NUMBER 1
#define ENDING_NUMBER 100

enum CASES { MULTIPLE_OF_THREE = 1, MULTIPLE_OF_FIVE, MULTIPLE_OF_BOTH };

/**
 * Tests if 'number' is a multiple of 'multiple', returns TRUE or FALSE accoringly
 */
static inline bool isMultiple(int number, const int multiple){
	return (number % multiple) == 0;
}

int main(void){

	/* Initalise a few variables */
	int currentNumber = STARTING_NUMBER;
	bool multipleOfFive = false;
	bool multipleOfThree = false;
	int result = 0;

	for(; currentNumber <= ENDING_NUMBER; currentNumber++){
		
		/* Test for multiples */
		multipleOfFive = isMultiple(currentNumber, 5);
		multipleOfThree = isMultiple(currentNumber, 3);
		
		/* Merge the test for multiples into two bit integer so we can identify which case we have
		with a switch statement
		   Our Cases are:
		   01 - Mulitple of Three
		   10 - Multiple of Five
		   11 - Multiple of Both 
		*/
		result = 0;
		result |=  multipleOfThree | (multipleOfFive << 1);

		/* Using the switch statement we are able to jump straight to the relevant case instead of
		messing around with cascaded if statements */
		switch(result){
			case MULTIPLE_OF_THREE:
				printf("Fizz\n");
				break;

			case MULTIPLE_OF_FIVE:
				printf("Buzz\n");
				break;

			case MULTIPLE_OF_BOTH:
				printf("FizzBuzz\n");
				break;

			/* If none of the above conditions are met then just print the number */
			default:
				printf("%i\n", currentNumber);
		}
	}

	return 0;
}