Python Random Password Generator (One Liner). #python #password

gistfile1.py

python -c "from random import choice; print ''.join([choice('abcdefghijklmnopqrstuvwxyz0123456789%^*(-_=+)') for i in range(32)])"

Updated for python 3.6

• Use Secrets Module
• Use string module to include all printable ASCII characters
• Add a length variable
  https://gist.github.com/urjeetpatel/60cee1e7dc509ead24e99f70de3b5bd7

For Python 3:

python -c "from random import choice; print(''.join([choice('abcdefghijklmnopqrstuvwxyz0123456789%^*(-_=+)') for i in range(32)]))"

Seems that the link above was taken down, or is private.

i re-added the correct link for the gist.

Personally, i feel better if you changed this from from random import choice to from secrets import choice.

In the Docs, it says

The secrets module is used for generating cryptographically strong random numbers suitable for managing data such as passwords, account authentication, security tokens, and related secrets.
In particular, secrets should be used in preference to the default pseudo-random number generator in the random module, which is designed for modelling and simulation, not security or cryptography.

Long time ago. And its not correctly escaped.

python3 -c "from secrets import choice; print (''.join([choice('abcdefghijklmnopqrstuvwxyz0123456789%^*(-_=+)') for i in range(32)]))"