[fun] various forms of ternary operator in JavaScript

[fun] various forms of ternary operator in JavaScript.js

// add your variants of
a ? b : c
// in comments :)
// a is boolean
// b and c - any type
// lazy evaluation isnt important

[c, b][a] doesn't work for me: it returns undefined, which seems expected. But [c, b][ ~ ~ a] works for true/false/1/0 and [c, b][!! ~ ~ a] works for negative numbers (at least if you expect them to resolve to true).

Shouldn't this:

[c, b][a]

Be this: (?)

[c, b][+!!a]

Or:

[b,c][+!a]

IMHO, this is the most readable ternary operation:

Array(2).concat(b, c)[String(a).match(/(t)|(f)/).join().split(',,').push(1)]

@padolsey It could simply be [c, b][+a], as the gist states that a is a boolean (not just a truthy/falsy value). But yeah, [c, b][a] doesn’t look right.

I believe

[c, b][a]

should be

[c, b][+a]

Edit: Damn you mathias! :)

@jneira I love that lambda calculus inspired version. How about this? (Credits to you, this is just sugar)

var lambdas = {
  true: function(x) {return function(y) {return x}},
  false: function(x) {return function(y) {return y}},
  ifthenelse: function (x) { return function(y) { return function(z) {return (x(y))(z)}}}
}
function ternary (a,b,c) {
  return lambdas.ifthenelse(lambdas[!!a])(function(_) {return b})(function(_){return c})()
}
console.log(ternary("a","b","c"))
// b
console.log(ternary(false,"b","c"))
//c

better, but credits to Alonzo Church!, we are simple mortals