Chris Demetriad chrisdemetriad

State Updates Are Asynchronous

The gist of it

You do this.

const handleEvent = e => {
  setState(e.target.value);
  console.log(state);
}

Regular Expression to Validate UK Number Plates

Regular Expression

(?<Current>^[A-Z]{2}[0-9]{2}[A-Z]{3}$)|(?<Prefix>^[A-Z][0-9]{1,3}[A-Z]{3}$)|(?<Suffix>^[A-Z]{3}[0-9]{1,3}[A-Z]$)|(?<DatelessLongNumberPrefix>^[0-9]{1,4}[A-Z]{1,2}$)|(?<DatelessShortNumberPrefix>^[0-9]{1,3}[A-Z]{1,3}$)|(?<DatelessLongNumberSuffix>^[A-Z]{1,2}[0-9]{1,4}$)|(?<DatelessShortNumberSufix>^[A-Z]{1,3}[0-9]{1,3}$)|(?<DatelessNorthernIreland>^[A-Z]{1,3}[0-9]{1,4}$)|(?<DiplomaticPlate>^[0-9]{3}[DX]{1}[0-9]{3}$)

For use in JavaScript (with named groups removed):

(^[A-Z]{2}[0-9]{2}\s?[A-Z]{3}$)|(^[A-Z][0-9]{1,3}[A-Z]{3}$)|(^[A-Z]{3}[0-9]{1,3}[A-Z]$)|(^[0-9]{1,4}[A-Z]{1,2}$)|(^[0-9]{1,3}[A-Z]{1,3}$)|(^[A-Z]{1,2}[0-9]{1,4}$)|(^[A-Z]{1,3}[0-9]{1,3}$)|(^[A-Z]{1,3}[0-9]{1,4}$)|(^[0-9]{3}[DX]{1}[0-9]{3}$)

	import time

	from telethon import TelegramClient, events

	# sample API_ID from https://github.com/telegramdesktop/tdesktop/blob/f98fdeab3fb2ba6f55daf8481595f879729d1b84/Telegram/SourceFiles/config.h#L220
	# or use your own
	api_id = 17349
	api_hash = '344583e45741c457fe1862106095a5eb'

	# fill in your own details here

	const Telegraf = require('telegraf')
	const bot = new Telegraf(process.env.BOT_TOKEN)

	function unescapeHtml(str){
	const map = {
	amp: '&',
	lt: '<',
	le: '≤',
	gt: '>',
	ge: '≥',

	function largestBinaryGap(num) {
	var bin = Math.abs(num).toString(2),
	finalMax = 0,
	currentMax;

	for (var i = 0; i < bin.length; i++) {
	currentMax = 0;
	while (bin[i] === "0") {
	++currentMax && ++i;
	}