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@cihancimen
Created November 26, 2012 00:54
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Check if an NSString contains an emoji character
- (BOOL)stringContainsEmoji:(NSString *)string {
__block BOOL returnValue = NO;
[string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:
^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {
const unichar hs = [substring characterAtIndex:0];
// surrogate pair
if (0xd800 <= hs && hs <= 0xdbff) {
if (substring.length > 1) {
const unichar ls = [substring characterAtIndex:1];
const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
if (0x1d000 <= uc && uc <= 0x1f77f) {
returnValue = YES;
}
}
} else if (substring.length > 1) {
const unichar ls = [substring characterAtIndex:1];
if (ls == 0x20e3) {
returnValue = YES;
}
} else {
// non surrogate
if (0x2100 <= hs && hs <= 0x27ff) {
returnValue = YES;
} else if (0x2B05 <= hs && hs <= 0x2b07) {
returnValue = YES;
} else if (0x2934 <= hs && hs <= 0x2935) {
returnValue = YES;
} else if (0x3297 <= hs && hs <= 0x3299) {
returnValue = YES;
} else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50) {
returnValue = YES;
}
}
}];
return returnValue;
}
@mi-Fei
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mi-Fei commented Dec 1, 2016

In ios7+, when input chinese using Pinyin:QWERTY/10 Key, it bugs. I found this problem as well, you can change into Chinese input way,I make a breakpoint and found the string change was number with gray color around, I just control the input in should change delegate method, so this code return me yes.

@mi-Fei
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mi-Fei commented Dec 1, 2016

I found the solution, just convert the string first
unichar unicodevalue = [text characterAtIndex:0];
NSString *str = [NSString stringWithCharacters:&unicodevalue length:1];
then use this str to judge

@TimorYang
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The U+d83e u Not included

@steve7688
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there are some new emojis added in iOS 16.Looks like this code need to be update

@szmichaelyb
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搜狗输入法的一些 emoji 表情,没有包含~

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