Print alphabet sans 'E'

ruby -e "('A'..'Z').each { |x| ('A'..x).each { |y| print y == 'E' ? 'X' : y }; puts }"

1. Outer loop 'A'..'Z' loops from A->Z sending a character to the variable 'x' in the block.
2. 'x' is used as the end point of the inner range, which is iterated over, yielding a character from A->'x' to the block as 'y'.
3. The block prints 'y', but checks first to see if it equals 'E' using a ternary operator (http://stackoverflow.com/questions/4252936/how-do-i-use-the-conditional-operator-in-ruby). If the character equals 'E', it switches it with 'X', otherwise it prints the original character, 'y'.
4. After each inner loop, puts prints a new line (by default).

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