Created
December 6, 2014 10:58
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One more: "I'm not sure if there should be a case for the constructor refl, because I get stuck when trying to solve the following unification problems"
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open import Function | |
open import Relation.Binary.PropositionalEquality | |
open import Data.Product | |
open import Data.String | |
open import Data.Bool | |
open import Data.Unit | |
record Level : Set where | |
constructor level | |
field | |
vars : Bool | |
lams : Bool | |
lets : Bool | |
infixl 6 _⊔_ | |
_⊔_ : Level → Level → Level | |
level v₁ lm₁ lt₁ ⊔ level v₂ lm₂ lt₂ = level (v₁ ∨ v₂) (lm₁ ∨ lm₂) (lt₁ ∨ lt₂) | |
pattern Core = level false false false | |
pattern Vars = level true false false | |
data Term : Level -> Set where | |
S : Term Core | |
K : Term Core | |
I : Term Core | |
App : ∀ {a b c} → Term a → Term b → a ⊔ b ≡ c → Term c | |
Var : String → Term Vars | |
Lam : ∀ {a b} → String → Term a → record a {lams = true} ≡ b → Term b | |
Let : ∀ {a b c} → String → Term a → Term b → record (a ⊔ b) {lets = true} ≡ c → Term c | |
infixr 1 _$₀_ | |
pattern _$₀_ a b = App {a = Core} {b = Core} a b refl | |
reduce : Term Core → Term Core | |
reduce (I $₀ x) = x | |
reduce (K $₀ x $₀ _) = x | |
reduce (S $₀ x $₀ y $₀ z) = x $₀ y $₀ (x $₀ z) | |
reduce (f $₀ x) = reduce f $₀ x | |
reduce t = t -- commenting this line still gives: | |
{- | |
I'm not sure if there should be a case for the constructor refl, | |
because I get stuck when trying to solve the following unification | |
problems (inferred index ≟ expected index): | |
level vars lams lets ⊔ level vars₁ lams₁ lets₁ ≟ level false false | |
false | |
when checking the definition of reduce | |
-} |
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