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@dproject21
Created January 20, 2013 08:14
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プロジェクトオイラー problem8の解答
line = "73167176531330624919225119674426574742355349194934" +
"96983520312774506326239578318016984801869478851843" +
"85861560789112949495459501737958331952853208805511" +
"12540698747158523863050715693290963295227443043557" +
"66896648950445244523161731856403098711121722383113" +
"62229893423380308135336276614282806444486645238749" +
"30358907296290491560440772390713810515859307960866" +
"70172427121883998797908792274921901699720888093776" +
"65727333001053367881220235421809751254540594752243" +
"52584907711670556013604839586446706324415722155397" +
"53697817977846174064955149290862569321978468622482" +
"83972241375657056057490261407972968652414535100474" +
"82166370484403199890008895243450658541227588666881" +
"16427171479924442928230863465674813919123162824586" +
"17866458359124566529476545682848912883142607690042" +
"24219022671055626321111109370544217506941658960408" +
"07198403850962455444362981230987879927244284909188" +
"84580156166097919133875499200524063689912560717606" +
"05886116467109405077541002256983155200055935729725" +
"71636269561882670428252483600823257530420752963450"
ans = 0
for (int i: 0 .. line.length() - 5) {
item = line.getAt(i).toInteger()
item2 = line.getAt(i + 1).toInteger()
item3 = line.getAt(i + 2).toInteger()
item4 = line.getAt(i + 3).toInteger()
item5 = line.getAt(i + 4).toInteger()
m = item * item2 * item3 * item4 * item5
if (ans < m) {
ans = m
}
}
println(ans)
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