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2차원 벡터 연속된 180도 범위의 모든 벡터를 쓰는 것이 정답이다.
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분수 찾기 이분검색 + 특정 수 이하의 기약분수 개수 구하기 (에라토스테네스의 체)
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https://github.com/nrc/r4cppp/blob/master/graphs/README.md | |
1. lifetime | |
- 1. User creates node/edge and provide their ref to Graph | |
- 2. Let Graph owns nodes/edges. | |
- Some helpers like from_adjacency_matrix() allocates on its own | |
2. mutability | |
3. Trait design |
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curl -L -s $1 | pdfnup --frame false --nup 2x1 /dev/stdin --outfile /dev/stdout | lpr -o sides=two-sided-short-edge |
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import pika | |
from pika.adapters.blocking_connection import BlockingConnection, BlockingChannel | |
import time | |
import atexit | |
from typing import List, Iterator, Tuple | |
from multiprocessing import Queue, Process | |
import queue | |
class RabbitConsumer(object): |
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package main | |
import ( | |
"fmt" | |
"sync" | |
"time" | |
"github.com/vbauerster/mpb" | |
"github.com/vbauerster/mpb/decor" | |
) |
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# SDS Expert-to-be | |
#### 강사. 강동구 | |
## 1회 | |
- 2차원 벡터 | |
연속된 180도 범위의 모든 벡터를 쓰는 것이 정답이다. | |
- 분수 찾기 | |
이분검색 + 특정 수 이하의 기약분수 개수 구하기 (에라토스테네스의 체) |