Gulp execute script PHP

gulpfile.js

var exec = require('child_process').exec

gulp.task('update-templates', function(){
    
    exec('php scripts/update-html.php', function (err, stdout, stderr) {
        console.log(stdout)
        console.log(stderr)
    })
})

gulp.task('default',['update-templates'])

Acually, it will freeze. You need to tell the process to it has finished.

gulp.task('update-templates', function(imdone){
    
    exec('php scripts/update-html.php', function (err, stdout, stderr) {
        console.log(stdout)
        console.log(stderr)
        imdone();
    })
})

@seigieu thanks for your contribution.