Skip to content

Instantly share code, notes, and snippets.

@federiccobrunelli

federiccobrunelli/index.html

Created April 5, 2020 17:58
Show Gist options
  • Save federiccobrunelli/08f646cf570692f7e4d39698bd0bc3b4 to your computer and use it in GitHub Desktop.
Save federiccobrunelli/08f646cf570692f7e4d39698bd0bc3b4 to your computer and use it in GitHub Desktop.
Download ZIP
JS Bin // source https://jsbin.com/jujenuf
Raw
index.html
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<script id="jsbin-javascript">
//MY REMIX
var numbers0 = [1,2,3,4,3,2,1]; //tot=16
var numbers1 = [1,100,50,-51,1,1]; //tot=102
var numbers2 = [1,2,3,4,5,6]; //tot=21
var numbers3 = [20,10,30,10,10,15,35]; //tot=130
let fromLeftSum = 0;
let fromRightSum = 0;
let countFromLeft = (arr) =>{
for (var i = 0; i < arr.length; i++) {
fromLeftSum += arr[i];
} return fromLeftSum;
};
let countFromRight = (arr) =>{
newArr = arr.reverse()
for (var i = 0; i < newArr.length; i++) {
fromRightSum += newArr[i];
} return fromRightSum;
};
let find
console.log(countFromLeft(numbers0))
console.log(countFromLeft(numbers1))
console.log(countFromLeft(numbers2))
console.log(countFromLeft(numbers3))
console.log(countFromRight(numbers0))
console.log(countFromRight(numbers1))
console.log(countFromRight(numbers2))
console.log(countFromRight(numbers3))
/*
console.log(reverseArray(numbers0))
console.log(reverseArray(numbers1))
console.log(reverseArray(numbers2))
console.log(reverseArray(numbers3))
*/
</script>
<script id="jsbin-source-javascript" type="text/javascript"> //MY REMIX
var numbers0 = [1,2,3,4,3,2,1]; //tot=16
var numbers1 = [1,100,50,-51,1,1]; //tot=102
var numbers2 = [1,2,3,4,5,6]; //tot=21
var numbers3 = [20,10,30,10,10,15,35]; //tot=130
let fromLeftSum = 0;
let fromRightSum = 0;
let countFromLeft = (arr) =>{
for (var i = 0; i < arr.length; i++) {
fromLeftSum += arr[i];
} return fromLeftSum;
};
let countFromRight = (arr) =>{
newArr = arr.reverse()
for (var i = 0; i < newArr.length; i++) {
fromRightSum += newArr[i];
} return fromRightSum;
};
let find
console.log(countFromLeft(numbers0))
console.log(countFromLeft(numbers1))
console.log(countFromLeft(numbers2))
console.log(countFromLeft(numbers3))
console.log(countFromRight(numbers0))
console.log(countFromRight(numbers1))
console.log(countFromRight(numbers2))
console.log(countFromRight(numbers3))
/*
console.log(reverseArray(numbers0))
console.log(reverseArray(numbers1))
console.log(reverseArray(numbers2))
console.log(reverseArray(numbers3))
*/
</script></body>
</html>
Raw
jsbin.jujenuf.js
//MY REMIX
var numbers0 = [1,2,3,4,3,2,1]; //tot=16
var numbers1 = [1,100,50,-51,1,1]; //tot=102
var numbers2 = [1,2,3,4,5,6]; //tot=21
var numbers3 = [20,10,30,10,10,15,35]; //tot=130
let fromLeftSum = 0;
let fromRightSum = 0;
let countFromLeft = (arr) =>{
for (var i = 0; i < arr.length; i++) {
fromLeftSum += arr[i];
} return fromLeftSum;
};
let countFromRight = (arr) =>{
newArr = arr.reverse()
for (var i = 0; i < newArr.length; i++) {
fromRightSum += newArr[i];
} return fromRightSum;
};
let find
console.log(countFromLeft(numbers0))
console.log(countFromLeft(numbers1))
console.log(countFromLeft(numbers2))
console.log(countFromLeft(numbers3))
console.log(countFromRight(numbers0))
console.log(countFromRight(numbers1))
console.log(countFromRight(numbers2))
console.log(countFromRight(numbers3))
/*
console.log(reverseArray(numbers0))
console.log(reverseArray(numbers1))
console.log(reverseArray(numbers2))
console.log(reverseArray(numbers3))
*/
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment