将由1 2 4 8 等或运算的结果分解

getBinary.js

function getBinary (num) {
  var n = Math.ceil(Math.sqrt(num))
  var codes = []
  for (let i = 0; i<= n; i++) {
    codes.push(Math.pow(2,i))
  }
  var res = []
  for (let k = codes.length -1; k >= 0; k--) {
    if (num >= codes[k]) {
      num = num - codes[k]
      res.push(codes[k])
    }
  }
  return res
}