Created
January 22, 2019 01:34
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class Solution { | |
public: | |
vector<double> medianSlidingWindow(vector<int>& nums, int k) { | |
int len = nums.size(); | |
multiset<int> smaller, larger; | |
vector<double> res; | |
for (int i = 0; i < len; ++i) | |
{ | |
//erase | |
if (i >= k) | |
{ | |
if (smaller.find(nums[i - k]) != smaller.end()) | |
//pass iterator here otherwise it will erase all elements with the same value | |
smaller.erase(smaller.find(nums[i - k])); | |
else | |
larger.erase(larger.find(nums[i - k])); | |
} | |
//insert | |
if (smaller.size() <= larger.size()) | |
{ | |
if (larger.empty() || *larger.begin() >= nums[i]) | |
smaller.insert(nums[i]); | |
else | |
{ | |
smaller.insert(*larger.begin()); | |
larger.erase(larger.begin()); | |
larger.insert(nums[i]); | |
} | |
} | |
else | |
{ | |
if (*smaller.rbegin() <= nums[i]) | |
larger.insert(nums[i]); | |
else | |
{ | |
larger.insert(*smaller.rbegin()); | |
smaller.erase(--smaller.end()); | |
smaller.insert(nums[i]); | |
} | |
} | |
if (i >= k - 1) | |
{ | |
auto test1 = *smaller.rbegin(), test2 = *larger.begin(); | |
double mid = k % 2 ? (smaller.size() > larger.size() ? *smaller.rbegin() : *larger.begin()) : | |
(static_cast<double>(*smaller.rbegin()) + static_cast<double>(*larger.begin())) / 2.0; | |
res.push_back(mid); | |
} | |
} | |
return res; | |
} | |
}; |
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