Created
November 6, 2019 04:02
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3 = the sum of 3 cubes ; a third solution, written in Common Lisp
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| ;;;; Previously there were only 2 known solutions for | |
| ;;;; a list of 3 numbers that when cubed and then added | |
| ;;;; together, equal 3. Here is a new one. | |
| (setq a 569936821221962380720) | |
| (setq b -0569936821113563493509) | |
| (setq c -472715493453327032) | |
| (defun cubed (x) | |
| "ay cubed plus bee cubed plus cee cubed equals 3 period" | |
| (* x x x)) | |
| (+ (cubed a) (cubed b) (cubed c)) |
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Incidentally, the previous 2 known solutions were:
(setq a 1)
(setq b 1)
(setq c 1)
and:
(setq a 4)
(setq b 4)
(setq c -5)
Significantly easier number to work with. Can't wait til we find solution 4!