Simple Python 3 debounce implementation

debounce.py

"""
@debounce(3)
def hi(name):
    print('hi {}'.format(name))


hi('dude')
time.sleep(1)
hi('mike')
time.sleep(1)
hi('mary')
time.sleep(1)
hi('jane')
"""
import time


def debounce(s):
    """Decorator ensures function that can only be called once every `s` seconds.
    """
    def decorate(f):
        t = None

        def wrapped(*args, **kwargs):
            nonlocal t
            t_ = time.time()
            if t is None or t_ - t >= s:
                result = f(*args, **kwargs)
                t = time.time()
                return result
        return wrapped
    return decorate

It's not a debounce. It's a throttle

@Ajk4
Thanks, you're totally right!

some test:

@debounce(2)
def hi(name):
    print('hi {}'.format(name))

for i in range(5):
    hi(f' {i}')
    print(f' {i} {time.time()}') 
    time.sleep(0.8)

outs:

hi  0
 0 1645192096.4046965
 1 1645192097.2055717
 2 1645192098.006468
hi  3
 3 1645192098.807511
 4 1645192099.6083152

have to say, if someone want to
　filter out process jitter, get the final state

this exactly not what they want.