range() without loops or recursion… or is it?

.js

(f => (g => g(g))(g => f(x => g(g)(x))))((x) => ([a, b, c = 1]) => a === b ? [a] : [a, ...x([a + c, b, c])])([1, 10])
// [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ]

// Note:  Functional programmers and mathematicians have known this trick
// for decades under the name of a Y combinator.  I did not invent this.
// I recommend deciphering this thing on your own, though.