Created
December 26, 2015 06:38
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tarjan
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| #include <cstdio> | |
| #include <algorithm> | |
| #include <cstring> | |
| #include <cmath> | |
| #include <queue> | |
| using namespace std; | |
| const int N = 100000+10, M = 1000000+10; | |
| int ans[N],e[2][N],rd[N],next[2][M],to[2][M],v[N],h[N]; | |
| int dfn[N],low[N],col[N],stack[N],sum[N],f[N],tot[2]; | |
| bool p[N],instack[N]; | |
| int n,m,k,Index,top,ctot; | |
| bool cmp(int x,int y) {return x>y;} | |
| void add(int x,int y,int kind) | |
| { | |
| tot[kind] ++; | |
| to[kind][tot[kind]] = y; | |
| next[kind][tot[kind]] = e[kind][x]; | |
| e[kind][x] = tot[kind]; | |
| } | |
| int gf(int x) | |
| { | |
| if (x!=h[x]) h[x] = gf(h[x]); | |
| return h[x]; | |
| } | |
| void link(int x,int y) | |
| { | |
| int i=gf(x), j=gf(y); | |
| if (i!=j) h[i]=j; | |
| } | |
| void tarjan(int x,int kind) | |
| { | |
| dfn[x] = low[x] = ++ Index; | |
| instack[x] = 1; | |
| stack[++ top] = x; | |
| for (int i=e[kind][x];i;i=next[kind][i]) | |
| { | |
| int y = to[kind][i]; | |
| if (col[y]) continue; | |
| if (instack[y]) low[x] = min(low[x],dfn[y]); | |
| else {tarjan(y,kind);low[x]=min(low[x],low[y]);} | |
| } | |
| if (dfn[x]==low[x]) | |
| { | |
| int y; | |
| ctot ++; | |
| do | |
| { | |
| y = stack[top --]; | |
| instack[y] = 0; | |
| sum[ctot] += v[y]; | |
| col[y] = ctot; | |
| } while (y!=x); | |
| } | |
| } | |
| void work(int x,int kind) | |
| { | |
| p[x] = 1; | |
| f[x] += sum[x]; | |
| for (int i=e[kind][x];i;i=next[kind][i]) | |
| { | |
| int y = to[kind][i]; | |
| link(x,y); | |
| rd[y] --; | |
| f[y] = max(f[y],f[x]); | |
| if (rd[y]==0) work(y,kind); | |
| } | |
| } | |
| int main() | |
| { | |
| freopen("azeroth.in","r",stdin); | |
| freopen("azeroth.out","w",stdout); | |
| scanf("%d%d",&n,&m); | |
| for (int i=1;i<=m;i ++) | |
| { | |
| int u,v; | |
| scanf("%d%d",&u,&v); | |
| if (u==v) continue; | |
| add(u,v,0); | |
| } | |
| for (int i=1;i<=n;i ++) scanf("%d",&v[i]); | |
| scanf("%d",&k); | |
| for (int i=1;i<=n;i ++) if (!col[i]) tarjan(i,0); | |
| for (int j=1;j<=n;j ++) | |
| for (int i=e[0][j];i;i=next[0][i]) | |
| { | |
| int u = j,v = to[0][i]; | |
| if (col[u]!=col[v]) | |
| { | |
| add(col[u],col[v],1); | |
| rd[col[v]] ++; | |
| } | |
| } | |
| //构造新图 | |
| for (int i=1;i<=ctot;i ++) h[i] = i; | |
| for (int i=1;i<=ctot;i ++) | |
| if (rd[i] == 0 && !p[i]) | |
| work(i,1); | |
| for (int i=1;i<=ctot;i ++) | |
| { | |
| ans[gf(i)] = max(ans[gf(i)],f[i]); | |
| } | |
| sort(ans+1,ans+1+ctot,cmp); | |
| for (int i=1;i<=min(k+1,ctot);i ++) | |
| ans[0] += ans[i]; | |
| printf("%d\n",ans[0]); | |
| return 0; | |
| } |
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