Curl - Get status code and response body

curl-get-status-code-and-response-body.sh

URL="http://stackoverflow.com/"

# store the whole response with the status at the and
HTTP_RESPONSE=$(curl --silent --write-out "HTTPSTATUS:%{http_code}" -X POST $URL)

# extract the body
HTTP_BODY=$(echo $HTTP_RESPONSE | sed -e 's/HTTPSTATUS\:.*//g')

# extract the status
HTTP_STATUS=$(echo $HTTP_RESPONSE | tr -d '\n' | sed -e 's/.*HTTPSTATUS://')

# print the body
echo "$HTTP_BODY"

# example using the status
if [ ! $HTTP_STATUS -eq 200  ]; then
  echo "Error [HTTP status: $HTTP_STATUS]"
  exit 1
fi

I've been able to get the http status by doing the following:

URL="http://stackoverflow.com/"
echo STATUS=$(curl -ILSso /dev/null -w '%{response_code}' $URL | head -n 1 | cut -d$' ' -f2)

Here is what I came up with:

    curl -sL -w ' { "statusCode": %{http_code}} ' -X POST "${headers[@]}" "${endpoint}" \
      -d "${body}"  "$curl_opts" | jq -ren '[inputs] | add'

the curl command produces:

{"message":"Change event processed","status":"success"}

I just add another object with the status code

{ "statusCode": 202} 

and have jq smush them together:

jq -ren '[inputs] | add'

So, if you use jq and slurp, you would get:

[
  {
    "message": "Change event processed",
    "status": "success"
  },
  {
    "statusCode": 202
  }
]

Instead, we squeeze them together and get:

jq -n '[inputs] | add'
{
  "message": "Change event processed",
  "status": "success",
  "statusCode": 202
}

we can then save and dump this and then use jq to return status code:

jq -re '.statusCode >= 200 and .statusCode < 300' > /dev/null

Remember: in bash the status code of the last command is the status code of the function