jimmychu0807

use std::str;

fn main() {
  // -- FROM: vec of chars --
  let src1: Vec<char> = vec!['j','{','"','i','m','m','y','"','}'];
  // to String
  let string1: String = src1.iter().collect::<String>();
  // to str
  let str1: &str = &src1.iter().collect::<String>();
  // to vec of byte

rylev

Learning Rust

The following is a list of resources for learning Rust as well as tips and tricks for learning the language faster.

Warning

Rust is not C or C++ so the way your accustomed to do things in those languages might not work in Rust. The best way to learn Rust is to embrace its best practices and see where that takes you.

The generally recommended path is to start by reading the books, and doing small coding exercises until the rules around borrow checking become intuitive. Once this happens, then you can expand to more real world projects. If you find yourself struggling hard with the borrow checker, seek help. It very well could be that you're trying to solve your problem in a way that goes against how Rust wants you to work.

AlwaysBCoding

// package.json
{
  "dependencies": {
    "web3": "0.17.0-alpha",
    "ethereumjs-util": "4.5.0"
  }
}

// keypairs.js
var EthUtil = require("ethereumjs-util")

leonardofed

A curated list of AWS resources to prepare for the AWS Certifications

A curated list of awesome AWS resources you need to prepare for the all 5 AWS Certifications. This gist will include: open source repos, blogs & blogposts, ebooks, PDF, whitepapers, video courses, free lecture, slides, sample test and many other resources.

---

OlegIlyenko

In this gist I would like to describe an idea for GraphQL subscriptions. It was inspired by conversations about subscriptions in the GraphQL slack channel and different GH issues, like #89 and #411.

Conceptual Model

At the moment GraphQL allows 2 types of queries:

• query
• mutation

Reference implementation also adds the third type: subscription. It does not have any semantics yet, so here I would like to propose one possible semantics interpretation and the reasoning behind it.

zmmbreeze

// http://stackoverflow.com/questions/11616630/json-stringify-avoid-typeerror-converting-circular-structure-to-json/11616993#11616993
var o = {};
o.o = o;

var cache = [];
JSON.stringify(o, function(key, value) {
    if (typeof value === 'object' && value !== null) {
        if (cache.indexOf(value) !== -1) {
            // Circular reference found, discard key
            return;