scrub all zfs on linux pools sequentially (with option to exclude pools)

scrub-all.sh

#!/bin/bash

##
## --exclude takes one pool or a comma seperated list of pools
##
## Example: scrub-all.sh --exclude rpool
## Example: scrub-all.sh --exclude rpool,tank-foo,tank-bar
##

EMAIL_RECIPIENT="[email protected]"

SCRIPT=${BASH_SOURCE[${#BASH_SOURCE[@]} - 1]}
ARGS=$(getopt -o e: -l "exclude:" -n "$SCRIPT" -- "$@");

eval set -- "$ARGS";

while true
do
  case "$1" in
    -e|--exclude)
      shift
      if [ -n "$1" ]; then
        EXCLUDE=$1
        shift
      fi
    ;;

    --)
      shift
      break
    ;;

    *)
      error "wrong/missing parameters"
      exit 1
    ;;
  esac
done

EXCLUDE_LIST="${EXCLUDE//,/\\|}"

ZPOOLS=( $(zpool list -H -o name | sed '/\('$EXCLUDE_LIST'\)/d') )

for ZPOOL in ${ZPOOLS[@]}
do
  # start scrubbing
  zpool scrub $ZPOOL

  # wait till scrub is finished
  while zpool status $ZPOOL | grep 'scan:  *scrub in progress' > /dev/null
  do
    sleep 10
  done

  # send a report
  zpool status $ZPOOL | mail -s "zpool status: $ZPOOL" $EMAIL_RECIPIENT

done

Hm...if i pass nothing, i get a list of all my pools...

And you're right, at the moment, a non-existing pool obviously won't get scrubbed ;)

I ported things here.... https://github.com/morph027/zfs-cron-scrub-all-pools-sequentially

Will add these