mylons

<core_identity> You are an assistant called Cluely, developed and created by Cluely, whose sole purpose is to analyze and solve problems asked by the user or shown on the screen. Your responses must be specific, accurate, and actionable. </core_identity>

<general_guidelines>

• NEVER use meta-phrases (e.g., "let me help you", "I can see that").
• NEVER summarize unless explicitly requested.
• NEVER provide unsolicited advice.
• NEVER refer to "screenshot" or "image" - refer to it as "the screen" if needed.
• ALWAYS be specific, detailed, and accurate.

mylons

type Corporation {
  name: String!
  mountains: [Mountain!]!
}

type Mountain {
  name: String!
  lifts: [Lift!]!
  trails: [Trail!]!
  employees: [Employee!]!

mylons

# Definition for singly-linked list.
class ListNode:
    def __init__(self, x):
        self.val = x
        self.next = None

class Solution:
    def reverseList(self, head: ListNode) -> ListNode:
        if head is None or head.next is None:
            return head

mylons

class Solution:
    def numUniqueEmails(self, emails: List[str]) -> int:
        uniques = set()
        for email in emails:
            uniques.add(parse_email(email))
        return len(uniques)


def parse_email(email: str) -> str:
    first_half, second_half = email.split('@')

mylons

class Solution:
    def searchRange(self, nums: List[int], target: int) -> List[int]:
        if len(nums) == 0:
            return [-1, -1]
        if len(nums) == 1:
            if target == nums[0]:
                return [0, 0]
        def binary_search(left, right):
            mid = math.floor((left + right) / 2)

mylons

class Solution:
    def strStr(self, haystack: str, needle: str) -> int:
        if needle == "":
            return 0
        if len(haystack) == 1 or len(haystack) == len(needle):
            return 0 if haystack == needle else -1

        if len(needle) > len(haystack):
            return -1

mylons

class Solution:
    def searchInsert(self, nums: List[int], target: int) -> int:
        if target < nums[0]: return 0
        elif target > nums[len(nums) - 1]: return len(nums)
        def recurse(left, right):
            if left >= right:
                if nums[left] < target: return left + 1
                elif nums[right] < target: return right + 1
                return right

mylons

class Solution:
    def lengthOfLongestSubstring(self, s):
        """
        :type s: str
        :rtype: int
        """
        if len(s) < 2: return len(s)
        subs = []
        for x in range(0, len(s)):

mylons

class Solution:
    def removeDuplicates(self, nums: List[int]) -> int:
        if len(nums) < 2: return len(nums)
        length = 1
        cur = 0
        future = 1
        while future < len(nums):
            if nums[cur] == nums[future]:
                nums[future] = 0

mylons

from typing import List

def int_to_array(x: int) -> List[int]:

    result = []
    while x > 0:
        tmp = x % 10
        result.append(tmp)
        x = int((x - tmp) / 10)