Medium Article Snippet

iterative_approach.js

const input = [1,3,5,7];

function product(inputArr) {
  const output = [];

  for (let i = 0; i < inputArr.length; i++) {
    let product = 1;
    for (let j = 0; j < inputArr.length; j++) {
      if (i !== j) {
        product *= inputArr[j];
      }
    }

    output.push(product);
    product = 1;
  }

  return output;
}

console.log(product(input));

Algorithmic Complexity:

Speed: O(n*2)
Space: O(n)

Next Approach: https://gist.github.com/naveedn/b16bd0a15ba089c58187eeacf4448efa