Created
January 12, 2019 23:39
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Newton iteration for multiple variablew
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#!/usr/bin/env python3 | |
import numpy | |
from numpy.linalg import inv | |
def newton_multi(func, x0, etol=1e-3, dx=1): | |
f0 = func(x0) | |
n = len(f0) | |
if n != len(x0): | |
raise Exception("func() must return a vector of same length as x0") | |
def can_exit(v): | |
for e in v: | |
if abs(e) > etol: return False | |
return True | |
x1 = lambda i, dx: numpy.array([ | |
0 if i != j else dx | |
for j in range(0, n) | |
]) + x0 | |
x = x0 | |
while not can_exit(f0): | |
jacob = [] | |
for i in range(0, n): | |
f1_i = func(x1(i, dx)) | |
df_i = f1_i - f0 | |
jacob.append(df_i / dx) | |
invjacob = inv(jacob) | |
ndx = numpy.dot(-f0, invjacob) | |
x += ndx | |
f0 = func(x) | |
return x, func(x) | |
if __name__ == "__main__": | |
from numpy import sin, cos, exp | |
def func(x): | |
x1, x2, x3 = x | |
return numpy.array([ | |
3*x1 - cos(x2*x3) - 1.5, | |
4*x1**2 - 625*x2**2 + 2*x3 - 1, | |
20*x3 + exp(-x1*x2) + 9 | |
]) | |
print(newton_multi(func, [0,0,0])) | |
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