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ostream& operator<<(ostream& os, const vector<int>& v){ | |
os << "[ "; | |
for(int i = 0; i<=v.size()-1; i++){ | |
os << "'" << v.at(i) << "'"; | |
if(i != v.size()-1) os << ','; | |
} | |
os << " ]"; | |
return os; | |
} | |
vector<int> rotateA(vector<int> a, int d){ | |
int n = a.size(); | |
if( d == 0 || d == n) return a; | |
d = d%n; | |
if(n == 2*d){ | |
// special case when n = 2d, then we just want to swap(i, i+d) | |
// to avoid an inf. loop | |
for(int i = 0; i < n/2; i++){ | |
int tmp = a.at(i); | |
a.at(i) = a.at(i+d); | |
a.at(i+d) = tmp; | |
} | |
} | |
else{ | |
//in all other cases, start from the end, put elem. into its destination, | |
// put elem. at dest into its new dest etc. | |
int i = n-1; | |
int cycle = n; | |
int curr = a.at(i); | |
while(cycle){ | |
int dest = i-d; | |
if(dest < 0) dest = n+dest; | |
int tmp = a.at(dest); | |
a.at(dest) = curr; | |
i = dest; | |
curr = tmp; | |
cycle--; | |
} | |
} | |
return a; | |
} | |
int main(){ | |
vector<int> items = {1,2,3,4,5,6}; | |
cout << rotateA(items, 3) << endl; | |
return 0; | |
} |
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