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January 29, 2024 12:25
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Update URL parameters in Python 3.
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import urllib.parse | |
url = "http://stackoverflow.com/search?q=question" | |
params = {'lang':'en','tag':'python'} | |
url_parts = list(urllib.parse.urlparse(url)) | |
query = dict(urllib.parse.parse_qsl(url_parts[4])) | |
query.update(params) | |
url_parts[4] = urllib.parse.urlencode(query) | |
print(urllib.parse.urlunparse(url_parts)) |
I think is more explicit to use url_parts.query
instead of url_parts[4]
import urllib.parse
url = "http://stackoverflow.com/search?q=question"
params = {'lang':'en','tag':'python'}
url_parts = urllib.parse.urlparse(url)
query = dict(urllib.parse.parse_qsl(url_parts.query))
query.update(params)
new_url = url_parts._replace(query=urllib.parse.urlencode(query)).geturl()
Thanks man! you the goat! 🚀
Fixed version:
import urllib.parse
url = "http://stackoverflow.com/search?q=question"
params = {'lang':'en','tag':'python'}
url_parts = urllib.parse.urlparse(url)
query = urllib.parse.parse_qs(url_parts.query, keep_blank_values=True)
query.update(params)
new_url = url_parts._replace(query=urllib.parse.urlencode(query, doseq=True)).geturl()
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furl is better