Created
June 4, 2021 03:52
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Armstrong Number check in python
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| n=int(input()) | |
| # 153=1^3+5^3+3^3 | |
| def armstrong(n): | |
| nums = [int(x)**3 for x in str(n)] ## separate the numbers and cube | |
| if sum(nums) == n: | |
| return True | |
| else: | |
| return False | |
| print(armstrong(n)) |
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