Day 8 Of 30 Days of Code - HackerRank - Python & Java

Dictionaries_and_Maps.java

/*
 Given  names and phone numbers, assemble a phone book that maps friends' names to their 
 respective phone numbers. You will then be given an unknown number of names to query your
 phone book for. For each  queried, print the associated entry from your phone book on a 
 new line in the form name=phoneNumber; if an entry for  is not found, print Not found instead.
 
 Java
 */
import java.util.*;
import java.io.*;

class Solution{
    public static void main(String []argh){
   Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        Map <String,Integer> myMap= new HashMap<String,Integer>();
        for(int i = 0; i < n; i++){
            String name = in.next();
            int phone = in.nextInt();
            myMap.put(name,phone);
        }
        while(in.hasNext()){
             
        String name = in.next();
            if (myMap.containsKey(name)) {
                int phone = myMap.get(name);
                System.out.println(name + "=" + phone);
            } else{
              System.out.println("Not found");
            }
        }
        in.close();
    }
}

Dictionaries_and_Maps.py

'''
 Given  names and phone numbers, assemble a phone book that maps friends' names to their 
 respective phone numbers. You will then be given an unknown number of names to query your
 phone book for. For each  queried, print the associated entry from your phone book on a 
 new line in the form name=phoneNumber; if an entry for  is not found, print Not found instead.
 
 Python
'''

phBook ={}
t = int(input())
for i in range(t):
    x,y = input().split(" ")
    phBook[x] = y
ls = []
for k in range(t):
    ls.append(input())

for j in ls:
    if(phBook.get(j)!=None):
        print(j+'='+phBook.get(j))
    else:
        print("Not Found")