Created
July 2, 2014 02:12
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Riot.js full router
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(function() { | |
var routes = []; | |
function on(route, fn) { | |
var keys = ['match']; | |
route = route.replace(/[\/\=\?\$\^]/g, '\\$&').replace(/\{(\w+)\}/g, function(match, key) { | |
keys.push(key); | |
return '(\\w+)'; | |
}); | |
routes.push({ re: RegExp(route), keys: keys, fn: fn }); | |
} | |
function emit(path) { | |
for (var i = 0, route, match; (route = routes[i]); i++) { | |
match = route.re.exec(path); | |
if (match) { | |
for (var j = 0, params = { path: path }, val; (val = match[j]); j++) { | |
params[route.keys[j]] = val; | |
} | |
route.fn(params); | |
} | |
} | |
} | |
riot.route = function(arg, fn) { | |
fn ? on(arg, fn) : typeof arg == 'function' ? on(".*", arg) : emit(arg); | |
return riot; | |
}; | |
})(); |
Besides those comments, It was cool that you used an array instead of an object for the routes that simplified a lot the only down side is because all routes will need to loop on the list there is no more O(1) in the best case scenario, but that is not an issue because the most routes will have params or wildcard.
wow i noticed that issue 3 wont happen because you will match all routes... I really like that ;)
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var
at the top of the function because that helps the compiler.riot.route({"/bla": function(params) { ... }, "/bla2": function () {...}});
this sintax lets you define several routes at once so there is no need to repeateriot.route(...)
over and over...typeof arg == 'function' ? on(".*", arg)
will allow you to define only one route "generic" route at a time, I think that is ok but the older implementation would allow you to to have as many as you want.riot.route(function(params){...})
all other routes defined after it will never be executed because the because the generic route will be catching everything.match
to the list of keys?route.fn(params);
.emit
and theon
function are doing too much, i would extract the regex creation and the params generation to a to other private functions, following the single responsibility principle.