Solved same frequency challenge using JavsScript

sameFrequency.js

/**
 * Write a function called sameFrequency. Given two positive integers, find out if the two numbers have the same frequency of digits.

The solution MUST have the following complexities:

Time: O(N)

Sample Input:

sameFrequency(182,281) // true
sameFrequency(34,14) // false
sameFrequency(3589578, 5879385) // true
sameFrequency(22,222) // false
 */
const sameFrequency = (num1, num2) => {
  if (!num1 || !num2) return false;
  if (num1 === num2) return true;

  let store1 = {};
  let store2 = {};

  let num1Arr = num1.toString().split("");
  let num2Arr = num2.toString().split("");

  for (let num of num1Arr) {
    store1[num] = (store1[num] || 0) + 1;
  }

  for (let num of num2Arr) {
    store2[num] = (store2[num] || 0) + 1;
  }

  for (let key in store1) {
    if (!(key in store2)) return false;

    if (store1[key] !== store2[key]) return false;
  }

  return true;
};

console.log(sameFrequency(34, 14)); // false
console.log(sameFrequency(182, 281)); // true
console.log(sameFrequency(3589578, 5879385)); // true
console.log(sameFrequency(22, 222)); // false