Days Off Calculator

dayz_off.py

"""
I wrote this script because I'm trying to figure out what day
would be the best day to take off if I only want to work four days
a week.

The best day here means I will get the most time off in the year if
I choose this day.

The holidays are German holidays and the extra days are company
holidays.
"""
from copy import copy
from collections import Counter
from datetime import date, UTC, timedelta
from pprint import pprint

HOLIDAYS = {
    date(2026, 1, 1),
    date(2026, 2, 13),
    date(2026, 8, 3),
    date(2026, 4, 3),
    date(2026, 4, 6),
    date(2026, 5, 1),
    date(2026, 5, 14),
    date(2026, 5, 22),
    date(2026, 5, 25),
    date(2026, 7, 6),
    date(2026, 10, 3),
    date(2026, 10, 16),
    date(2026, 12, 25),
    date(2026, 12, 26),
}

WEEKEND = {"Sat", "Sun"}

def main():
    days_off_counter = Counter()
    days_off = {
        "Mon",
        "Tue",
        "Wed",
        "Thu",
        "Fri",
    }

    for day in days_off:
        start_day = date(2026, 1, 1)
        current_day = copy(start_day)

        while current_day.year < start_day.year + 1:
            current_day_of_week = current_day.strftime("%a")

            if current_day in HOLIDAYS and current_day not in WEEKEND:
                days_off_counter[day] += 1

            elif current_day_of_week == day:
                days_off_counter[day] += 1

            current_day += timedelta(days=1)

    pprint(days_off_counter)

if __name__ == '__main__':
    main()