Created
September 23, 2024 16:29
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func manachersAlgorithmLeetcode(_ s: String) -> String { | |
let sPrime = ["#"] + s.map { String($0) }.joined(separator: "#").map { String($0) } + ["#"] | |
let n = sPrime.count | |
var palindromeRadii = Array(repeating: 0, count: n) | |
var center = 0 | |
var rightBound = 0 | |
var maxLength = 0 | |
var maxIndex = 0 | |
for i in 1..<n { | |
let mirror = 2 * center - i | |
let leftBound = center - (rightBound - center) | |
// center = (l + r) / 2 | |
// center * 2 = l + r | |
// center * 2 - r = l | |
// l = center * 2 - r | |
print(sPrime.joined()) | |
var padding = Array(repeating: " ", count: n) | |
padding[rightBound] = "r" | |
padding[center] = "c" | |
padding[i] = "i" | |
padding[leftBound] = "l" | |
if mirror >= 0 { | |
padding[mirror] = "m" | |
} | |
print(padding.joined()) | |
// If we are within the bounds of the palindrome centered at `center` | |
if i < rightBound { | |
// We can know that the radius of the palindrome at i at least the same as | |
// the palindrome at mirror as long as the palindrome at mirror is within the bounds | |
// of the palindrome at center, otherwise restrict the size to the bounds of the | |
// palindrome at center | |
palindromeRadii[i] = min(rightBound - i, palindromeRadii[mirror]) | |
} | |
// Search outwards from there, since the palindrome could be larger | |
while | |
i + 1 + palindromeRadii[i] < n | |
&& i - 1 - palindromeRadii[i] >= 0 | |
&& sPrime[i + 1 + palindromeRadii[i]] == sPrime[i - 1 - palindromeRadii[i]] | |
{ | |
palindromeRadii[i] += 1 | |
if palindromeRadii[i] > maxLength { | |
maxLength = palindromeRadii[i] | |
maxIndex = i | |
} | |
} | |
// If the palindrome at i extends past the right bound of the palindrome at center | |
if i + palindromeRadii[i] > rightBound { | |
// Update the center and the new furthest known rightbound | |
center = i | |
rightBound = i + palindromeRadii[i] | |
} | |
} | |
let centerIndex = maxIndex | |
let startIndex = (centerIndex - maxLength) / 2 | |
let longestPalindrome = s.map(String.init)[startIndex..<startIndex+maxLength].joined() | |
return longestPalindrome | |
} |
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