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June 30, 2012 06:55
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memit: magic memory usage benching for IPython
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# Author: Vlad Niculae <[email protected]> | |
# Makes use of memory_profiler from Fabian Pedregosa | |
# available at https://github.com/fabianp/memory_profiler | |
from IPython.core.magic import Magics, line_magic, magics_class | |
class MemMagics(Magics): | |
@line_magic | |
def memit(self, line='', setup='pass'): | |
"""Measure memory usage of a Python statement | |
Usage, in line mode: | |
%memit [-ir<R>t<T>] statement | |
Options: | |
-r<R>: repeat the loop iteration <R> times and take the best result. | |
Default: 3 | |
-i: run the code in the current environment, without forking a new | |
process. This is required on some MacOS versions of Accelerate if your | |
line contains a call to `np.dot`. | |
-t<T>: timeout after <T> seconds. Unused if `-i` is active. | |
Default: None | |
Examples | |
-------- | |
:: | |
In [1]: import numpy as np | |
In [2]: %memit np.zeros(1e7) | |
maximum of 3: 76.402344 MB per loop | |
In [3]: %memit np.ones(1e6) | |
maximum of 3: 7.820312 MB per loop | |
In [4]: %memit -r 10 np.empty(1e8) | |
maximum of 10: 0.101562 MB per loop | |
In [5]: memit -t 3 while True: pass; | |
Subprocess timed out. | |
Subprocess timed out. | |
Subprocess timed out. | |
ERROR: all subprocesses exited unsuccessfully. Try again with the | |
`-i` option. | |
maximum of 3: -inf MB per loop | |
""" | |
opts, stmt = self.parse_options(line, 'r:t:i', posix=False, | |
strict=False) | |
repeat = int(getattr(opts, 'r', 3)) | |
if repeat < 1: | |
repeat == 1 | |
timeout = int(getattr(opts, 't', 0)) | |
if timeout <= 0: | |
timeout = None | |
run_in_place = hasattr(opts, 'i') | |
# Don't depend on multiprocessing: | |
try: | |
import multiprocessing as pr | |
from multiprocessing.queues import SimpleQueue | |
q = SimpleQueue() | |
except ImportError: | |
class ListWithPut(list): | |
"Just a list where the `append` method is aliased to `put`." | |
def put(self, x): | |
self.append(x) | |
q = ListWithPut() | |
print ('WARNING: cannot import module `multiprocessing`. Forcing ' | |
'the `-i` option.') | |
run_in_place = True | |
ns = self.shell.user_ns | |
def _get_usage(q, stmt, setup='pass', ns={}): | |
from memory_profiler import memory_usage as _mu | |
try: | |
exec setup in ns | |
_mu0 = _mu()[0] | |
exec stmt in ns | |
_mu1 = _mu()[0] | |
q.put(_mu1 - _mu0) | |
except Exception as e: | |
q.put(float('-inf')) | |
raise e | |
if run_in_place: | |
for _ in xrange(repeat): | |
_get_usage(q, stmt, ns=ns) | |
else: | |
# run in consecutive subprocesses | |
at_least_one_worked = False | |
for _ in xrange(repeat): | |
p = pr.Process(target=_get_usage, args=(q, stmt, 'pass', ns)) | |
p.start() | |
p.join(timeout=timeout) | |
if p.exitcode == 0: | |
at_least_one_worked = True | |
else: | |
p.terminate() | |
if p.exitcode == None: | |
print 'Subprocess timed out.' | |
else: | |
print 'Subprocess exited with code %d.' % p.exitcode | |
q.put(float('-inf')) | |
if not at_least_one_worked: | |
print ('ERROR: all subprocesses exited unsuccessfully. Try ' | |
'again with the `-i` option.') | |
usages = [q.get() for _ in xrange(repeat)] | |
usage = max(usages) | |
print u"maximum of %d: %f MB per loop" % (repeat, usage) | |
if __name__ == '__main__': | |
ip = get_ipython() | |
ip.register_magics(MemMagics) |
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