Skip to content

Instantly share code, notes, and snippets.

@victorkurauchi
Created March 25, 2020 15:48
Show Gist options
  • Save victorkurauchi/71623edb1b0a9e679b817b107e973954 to your computer and use it in GitHub Desktop.
Save victorkurauchi/71623edb1b0a9e679b817b107e973954 to your computer and use it in GitHub Desktop.
Score 100/100
// you can write to stdout for debugging purposes, e.g.
// console.log('this is a debug message');
function solution(A) {
// write your code in JavaScript (Node.js 8.9.4)
let total = A.length;
let occurences = {}
let indexes = [];
for (let i = 0; i < A.length; i++) {
let elm = A[i]
if (!occurences[elm]) {
occurences[elm] = {
count: 0,
indexes: [],
}
}
occurences[elm].count += 1;
occurences[elm].indexes.push(i);
}
let dominator = Object.keys(occurences).find(idx => {
return occurences[idx].count > (total/2)
})
// console.log(occurences[dominator].indexes)
return dominator ? occurences[dominator].indexes[0] : -1
}
/*
An array A consisting of N integers is given. The dominator of array A is the value that occurs in more than half of the elements of A.
For example, consider array A such that
A[0] = 3 A[1] = 4 A[2] = 3
A[3] = 2 A[4] = 3 A[5] = -1
A[6] = 3 A[7] = 3
The dominator of A is 3 because it occurs in 5 out of 8 elements of A (namely in those with indices 0, 2, 4, 6 and 7) and 5 is more than a half of 8.
Write a function
function solution(A);
that, given an array A consisting of N integers, returns index of any element of array A in which the dominator of A occurs. The function should return −1 if array A does not have a dominator.
For example, given array A such that
A[0] = 3 A[1] = 4 A[2] = 3
A[3] = 2 A[4] = 3 A[5] = -1
A[6] = 3 A[7] = 3
the function may return 0, 2, 4, 6 or 7, as explained above.
Write an efficient algorithm for the following assumptions:
N is an integer within the range [0..100,000];
each element of array A is an integer within the range [−2,147,483,648..2,147,483,647].
*/
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment