vikmeup

Keybase proof

I hereby claim:

• I am vikmeup on github.
• I am vikmeup (https://keybase.io/vikmeup) on keybase.
• I have a public key ASCBVagsVv63-cn9_uugHFFfMGjj5aIrnGiVDhjxDm-L0go

To claim this, I am signing this object:

vikmeup

func generate(numRows: Int) -> [[Int]] {
        var results = [[Int]]()
        if (numRows == 0) {
            return results
        }
        for i in 0..<numRows {
            var currentResults = [Int]()
            for j in 0...i {
                if (i > 1 && j > 0 && j < i) {
                    let value = results[i-1][j] + results[i-1][j-1]

vikmeup

func removeDuplicates(inout nums: [Int]) -> Int {
    var dict = Dictionary<Int,Int>()
    var repeatedCount = 0
    for i in 0..<nums.count {
        let curIndex = i-repeatedCount
        let v = nums[curIndex]
        if let value = dict[v] {
            dict[v] = value + 1
            if (value > 1) {
                repeatedCount += 1

vikmeup

func flipMatrix(inout matrix: [[Int]]) {
    let n = matrix.count
    for i in 0..<n {
        for j in i+1..<n {
            let temp = matrix[i][j]
            matrix[i][j] = matrix[j][i]
            matrix[j][i] = temp
        }
    }
}

vikmeup

func isValid(s: String) -> Bool {
    struct Stack<Element> {
        var items = [Element]()
        mutating func push(item: Element) {
            items.append(item)
        }
        mutating func pop() -> Element {
            return items.removeLast()
        }
    }

vikmeup

func isPalindrome(s: String) -> Bool {
  let cleanString = s.componentsSeparatedByCharactersInSet(NSCharacterSet.alphanumericCharacterSet().invertedSet).joinWithSeparator("")
  return Bool(String(cleanString.characters).lowercaseString == String(cleanString.characters.reverse()).lowercaseString)
}

vikmeup

class Solution {
    func compareVersion(version1: String, _ version2: String) -> Int {
        var v1 = version1.characters.split(".").map { Int(String($0)) }
        var v2 = version2.characters.split(".").map { Int(String($0)) }
        var result = 0
        for i in 0..<max(v1.count,v2.count) {
            let left = i >= v1.count ? 0 : v1[i]
            let right = i >= v2.count ? 0 : v2[i]
            
            if (left == right) {

vikmeup

Keybase proof

I hereby claim:

• I am vikmeup on github.
• I am vikmeup (https://keybase.io/vikmeup) on keybase.
• I have a public key whose fingerprint is E703 63DF 3349 F445 E1BA DE8B 477E 2D8B 8546 E91E

To claim this, I am signing this object:

vikmeup

Title: 

Scroll Feed: Reader of interesting and funny news, facts, photos, video, articles

Keywords: 

social,9gag,fun,science,girls,vintage,fashion,art,rss,magazine,read,travel,music,tech,sport,abc,cnn

Description:

vikmeup

<?php 
$apnsHost = 'gateway.sandbox.push.apple.com';
$apnsCert = 'apns-dev.pem';
$apnsPort = 2195;

$streamContext = stream_context_create();
stream_context_set_option($streamContext, 'ssl', 'local_cert', $apnsCert);

$apns = stream_socket_client('ssl://' . $apnsHost . ':' . $apnsPort, $error, $errorString, 2, STREAM_CLIENT_CONNECT, $streamContext);