Viktor Bezdek viktorbezdek

This formula ensures that each logo will occupy the same area, making them appear visually identical in size.

$$[ \text{New Height} = \left( \frac{\text{Target Area}}{\text{Original Width}} \right)^{0.5} ]$$

$$[ \text{New Width} = \text{Original Width} \times \left( \frac{\text{New Height}}{\text{Original Height}} \right) ]$$

I hereby claim:

To claim this, I am signing this object:

	type Cell = 0 \| 1;
	type Grid = Cell[][];

	// Utility to transpose a matrix (swap rows and columns)
	const transpose = <T>(grid: T[][]): T[][] =>
	grid[0].map((_, i) => grid.map(row => row[i]));

	// Create a function to get neighboring cells of a given coordinate
	const neighbors = (grid: Grid) => ([x, y]: [number, number]): [number, number][] =>
	[-1, 0, 1]

	// Conway's Game of Life in functional TypeScript

	// Game board size
	const ROWS = 10;
	const COLS = 10;

	// Game board represented as 2D array
	type Board = boolean[][];

	// Create empty board

	const _ = require("lodash/fp")

	const sample = Array.from({ length: 90000 }).map((_, i) => i)

	var nativeStart
	var nativeDuration
	;(() => {
	nativeStart = process.hrtime.bigint()
	for (let x = 0; x <= 10000; x++) {
	sample.map((n) => n * 2)

	'use strict';
	const MD5 = (str) => {
	const currentNick = M(V(Y(X(str), 8 * str.length)));
	return currentNick.toLowerCase();
	};
	/**
	* @param {string} b
	* @return {?}
	*/
	function M(b) {


	function boardGet(arr, i, j) {
	if (i < 0 \|\| j < 0 \|\| i >= arr.length \|\| j >= arr[i].length) {
	return 0
	}
	return arr[i][j]
	}

	function countNeighbors(board, i, j) {
	return (

	function conwaysGameOfLife(board) {
	var newBoard = []
	for (var i = 0; i < board.length; i++) {
	newBoard.push([])
	for (var j = 0; j < board[i].length; j++) {
	newBoard[i].push(0)
	}
	}

	for (var i = 0; i < board.length; i++) {